0=-4.9x^2+4.43x

Solution for 0=-4.9x^2+4.43x equation:

0=-4.9x^2+4.43x

We move all terms to the left:

0-(-4.9x^2+4.43x)=0

We add all the numbers together, and all the variables

-(-4.9x^2+4.43x)=0

We get rid of parentheses

4.9x^2-4.43x=0

a = 4.9; b = -4.43; c = 0;
Δ = b2-4ac
Δ = -4.432-4·4.9·0
Δ = 19.6249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.43)-\sqrt{19.6249}}{2*4.9}=\frac{4.43-\sqrt{19.6249}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.43)+\sqrt{19.6249}}{2*4.9}=\frac{4.43+\sqrt{19.6249}}{9.8}
$